# Tips to crack GRE Quant | GRE Quantitative Syllabus

The GRE Quant Section assesses your Basic Math skills, Your understanding about Mathematical Concepts and ability to solve the Problems using Quantitative methods.

The Topics covered in GRE Quantitative Syllabus are: Data analysis, Algebra, Arithmetic and Geometry.

Find the Useful Tips and Suggestions,Aspirants Questions and Experts Answers about GRE.

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Here quartile means the number that separates 25% of the given data. Given data is 15, 27, 40, 42,45,46,48,51,54,56,225.

~Q1 is first quartile = median of {lower half of data}

Q2 is second quartile = median of given data

Q3 is third quartile = median of{upper half of the data}

Q1 =median of {15,27,40,42,45,46} = (40 +42)/2 = 41.

Q2 = (46+48)/2 = 47

Q3 = median of {48,48,51,54,56,225} = (51 +54)/2 = 52.5

Therefore, The inter quartile range = Q3 – Q1 = 52.5 – 41 = 11.5

I didn’t really get the point of taking this sign convention. As I know of my basic knowledge of

mathematics the square root of a number has to be taken both (+-) but in the case of number theory only positive square root has been considered but here both positive and negative values are considered. Why?

There are two questions A= .

Then find A?

The answer here is 6 because the square root is always taken to be positive.

But when we solve a problem such that A2=36

then in this case the values of A that satisfy this are both + and – A.

This is the main difference between the two.

When it is asked to calculate clearly the square root then you have to take only the positive value and if in case you are solving some equation and then see that you get a relation A2=36 then you have to take both the values.

(30/100) p>3*2q -is this equation not correct mam..I couldn’t understand esp this type of questions..feeling bit difficult to decode it from sentences to equation..can u make it little clear and add give me more easily understandable questions to make this part perfect

The question says,

“If p is 30% larger than a third of twice q, express 2q/p as a fraction, decimal and %.”

The question requires you to find, 2q/p with the help of the given information and represent the answer as fraction, decimal and %.

Solution:

• “p is” means “p =”
• “30% lager than” means “130/100”
• “of” means “Multiply”
• “third of” means “1/3 multiply”
• “twice q” means “2q”

Now lets join the sentence,

p is 30% larger than a third of twice q

It is nothing but

p = (130/100) × (1/3) × (2q)

With the help of this equation, find the answer for 2q/p

2q/p = 300/130

2q/p = 30/13

As per the question, we want the value for 2q/p in fraction, decimal and %

2q/p in fraction = 30/13

2q/p in decimal = 30/13 = 2.30

2q/p in % = (2.31)(100) = 230%

Hope it is clear.

When I use the normal tabulation method for this problem, I get 0.36 days. Can you please explain how to do this problem, using the normal method?

You can solve this problem as Work-Men-Effort Problem.

Let W denote the unit work done, that is digging a trenches of size 1 ft long , 1 ft wide and 1 ft deep.

E denotes the efficiency of one soldier for doing a work unit and T denotes the time taken to complete the work

Now the first statement is “30 soldiers can dig 10 trenches of size 8 ft long by 3 ft wide by 3 ft deep in a 1/2 day working 8 hours per day.”

Here the total work done = 10 × 8 × 3 × 3 × W = 720W

(Total Work done) = (Total Efficiency) × (Time Taken)

720W = 30E × ( × 8)

W =  × E =  × E

It is asked that “How many hours will 20 soldiers take to dig 18 trenches of size 6 feet long by 2 ft wide by 2 ft deep, working 10 hours a day”

Here the work done is 18 × 6 × 2 × 2W = 432W

Hence here equation is 432W = 20 × E × (10 × d)

432() = 20 × E × (T)

72 = 20T

T = 3.6 hours